Optimal. Leaf size=200 \[ \frac {105 b^{3/2} d^3 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{8 (b c-a d)^{11/2}}-\frac {105 b d^3}{8 \sqrt {c+d x} (b c-a d)^5}-\frac {35 d^3}{8 (c+d x)^{3/2} (b c-a d)^4}-\frac {21 d^2}{8 (a+b x) (c+d x)^{3/2} (b c-a d)^3}+\frac {3 d}{4 (a+b x)^2 (c+d x)^{3/2} (b c-a d)^2}-\frac {1}{3 (a+b x)^3 (c+d x)^{3/2} (b c-a d)} \]
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Rubi [A] time = 0.13, antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 3, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {51, 63, 208} \begin {gather*} \frac {105 b^{3/2} d^3 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{8 (b c-a d)^{11/2}}-\frac {105 b d^3}{8 \sqrt {c+d x} (b c-a d)^5}-\frac {35 d^3}{8 (c+d x)^{3/2} (b c-a d)^4}-\frac {21 d^2}{8 (a+b x) (c+d x)^{3/2} (b c-a d)^3}+\frac {3 d}{4 (a+b x)^2 (c+d x)^{3/2} (b c-a d)^2}-\frac {1}{3 (a+b x)^3 (c+d x)^{3/2} (b c-a d)} \end {gather*}
Antiderivative was successfully verified.
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Rule 51
Rule 63
Rule 208
Rubi steps
\begin {align*} \int \frac {1}{(a+b x)^4 (c+d x)^{5/2}} \, dx &=-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}-\frac {(3 d) \int \frac {1}{(a+b x)^3 (c+d x)^{5/2}} \, dx}{2 (b c-a d)}\\ &=-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}+\frac {3 d}{4 (b c-a d)^2 (a+b x)^2 (c+d x)^{3/2}}+\frac {\left (21 d^2\right ) \int \frac {1}{(a+b x)^2 (c+d x)^{5/2}} \, dx}{8 (b c-a d)^2}\\ &=-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}+\frac {3 d}{4 (b c-a d)^2 (a+b x)^2 (c+d x)^{3/2}}-\frac {21 d^2}{8 (b c-a d)^3 (a+b x) (c+d x)^{3/2}}-\frac {\left (105 d^3\right ) \int \frac {1}{(a+b x) (c+d x)^{5/2}} \, dx}{16 (b c-a d)^3}\\ &=-\frac {35 d^3}{8 (b c-a d)^4 (c+d x)^{3/2}}-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}+\frac {3 d}{4 (b c-a d)^2 (a+b x)^2 (c+d x)^{3/2}}-\frac {21 d^2}{8 (b c-a d)^3 (a+b x) (c+d x)^{3/2}}-\frac {\left (105 b d^3\right ) \int \frac {1}{(a+b x) (c+d x)^{3/2}} \, dx}{16 (b c-a d)^4}\\ &=-\frac {35 d^3}{8 (b c-a d)^4 (c+d x)^{3/2}}-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}+\frac {3 d}{4 (b c-a d)^2 (a+b x)^2 (c+d x)^{3/2}}-\frac {21 d^2}{8 (b c-a d)^3 (a+b x) (c+d x)^{3/2}}-\frac {105 b d^3}{8 (b c-a d)^5 \sqrt {c+d x}}-\frac {\left (105 b^2 d^3\right ) \int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx}{16 (b c-a d)^5}\\ &=-\frac {35 d^3}{8 (b c-a d)^4 (c+d x)^{3/2}}-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}+\frac {3 d}{4 (b c-a d)^2 (a+b x)^2 (c+d x)^{3/2}}-\frac {21 d^2}{8 (b c-a d)^3 (a+b x) (c+d x)^{3/2}}-\frac {105 b d^3}{8 (b c-a d)^5 \sqrt {c+d x}}-\frac {\left (105 b^2 d^2\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{8 (b c-a d)^5}\\ &=-\frac {35 d^3}{8 (b c-a d)^4 (c+d x)^{3/2}}-\frac {1}{3 (b c-a d) (a+b x)^3 (c+d x)^{3/2}}+\frac {3 d}{4 (b c-a d)^2 (a+b x)^2 (c+d x)^{3/2}}-\frac {21 d^2}{8 (b c-a d)^3 (a+b x) (c+d x)^{3/2}}-\frac {105 b d^3}{8 (b c-a d)^5 \sqrt {c+d x}}+\frac {105 b^{3/2} d^3 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{8 (b c-a d)^{11/2}}\\ \end {align*}
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Mathematica [C] time = 0.02, size = 52, normalized size = 0.26 \begin {gather*} -\frac {2 d^3 \, _2F_1\left (-\frac {3}{2},4;-\frac {1}{2};-\frac {b (c+d x)}{a d-b c}\right )}{3 (c+d x)^{3/2} (a d-b c)^4} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.87, size = 304, normalized size = 1.52 \begin {gather*} -\frac {d^3 \left (16 a^4 d^4-144 a^3 b d^3 (c+d x)-64 a^3 b c d^3+96 a^2 b^2 c^2 d^2-693 a^2 b^2 d^2 (c+d x)^2+432 a^2 b^2 c d^2 (c+d x)-64 a b^3 c^3 d-432 a b^3 c^2 d (c+d x)-840 a b^3 d (c+d x)^3+1386 a b^3 c d (c+d x)^2+16 b^4 c^4+144 b^4 c^3 (c+d x)-693 b^4 c^2 (c+d x)^2-315 b^4 (c+d x)^4+840 b^4 c (c+d x)^3\right )}{24 (c+d x)^{3/2} (b c-a d)^5 (-a d-b (c+d x)+b c)^3}-\frac {105 b^{3/2} d^3 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x} \sqrt {a d-b c}}{b c-a d}\right )}{8 (a d-b c)^{11/2}} \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 1.43, size = 1840, normalized size = 9.20
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 1.20, size = 432, normalized size = 2.16 \begin {gather*} -\frac {105 \, b^{2} d^{3} \arctan \left (\frac {\sqrt {d x + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{8 \, {\left (b^{5} c^{5} - 5 \, a b^{4} c^{4} d + 10 \, a^{2} b^{3} c^{3} d^{2} - 10 \, a^{3} b^{2} c^{2} d^{3} + 5 \, a^{4} b c d^{4} - a^{5} d^{5}\right )} \sqrt {-b^{2} c + a b d}} - \frac {315 \, {\left (d x + c\right )}^{4} b^{4} d^{3} - 840 \, {\left (d x + c\right )}^{3} b^{4} c d^{3} + 693 \, {\left (d x + c\right )}^{2} b^{4} c^{2} d^{3} - 144 \, {\left (d x + c\right )} b^{4} c^{3} d^{3} - 16 \, b^{4} c^{4} d^{3} + 840 \, {\left (d x + c\right )}^{3} a b^{3} d^{4} - 1386 \, {\left (d x + c\right )}^{2} a b^{3} c d^{4} + 432 \, {\left (d x + c\right )} a b^{3} c^{2} d^{4} + 64 \, a b^{3} c^{3} d^{4} + 693 \, {\left (d x + c\right )}^{2} a^{2} b^{2} d^{5} - 432 \, {\left (d x + c\right )} a^{2} b^{2} c d^{5} - 96 \, a^{2} b^{2} c^{2} d^{5} + 144 \, {\left (d x + c\right )} a^{3} b d^{6} + 64 \, a^{3} b c d^{6} - 16 \, a^{4} d^{7}}{24 \, {\left (b^{5} c^{5} - 5 \, a b^{4} c^{4} d + 10 \, a^{2} b^{3} c^{3} d^{2} - 10 \, a^{3} b^{2} c^{2} d^{3} + 5 \, a^{4} b c d^{4} - a^{5} d^{5}\right )} {\left ({\left (d x + c\right )}^{\frac {3}{2}} b - \sqrt {d x + c} b c + \sqrt {d x + c} a d\right )}^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 319, normalized size = 1.60 \begin {gather*} \frac {55 \sqrt {d x +c}\, a^{2} b^{2} d^{5}}{8 \left (a d -b c \right )^{5} \left (b d x +a d \right )^{3}}-\frac {55 \sqrt {d x +c}\, a \,b^{3} c \,d^{4}}{4 \left (a d -b c \right )^{5} \left (b d x +a d \right )^{3}}+\frac {55 \sqrt {d x +c}\, b^{4} c^{2} d^{3}}{8 \left (a d -b c \right )^{5} \left (b d x +a d \right )^{3}}+\frac {35 \left (d x +c \right )^{\frac {3}{2}} a \,b^{3} d^{4}}{3 \left (a d -b c \right )^{5} \left (b d x +a d \right )^{3}}-\frac {35 \left (d x +c \right )^{\frac {3}{2}} b^{4} c \,d^{3}}{3 \left (a d -b c \right )^{5} \left (b d x +a d \right )^{3}}+\frac {41 \left (d x +c \right )^{\frac {5}{2}} b^{4} d^{3}}{8 \left (a d -b c \right )^{5} \left (b d x +a d \right )^{3}}+\frac {105 b^{2} d^{3} \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{8 \left (a d -b c \right )^{5} \sqrt {\left (a d -b c \right ) b}}+\frac {8 b \,d^{3}}{\left (a d -b c \right )^{5} \sqrt {d x +c}}-\frac {2 d^{3}}{3 \left (a d -b c \right )^{4} \left (d x +c \right )^{\frac {3}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.64, size = 334, normalized size = 1.67 \begin {gather*} \frac {\frac {231\,b^2\,d^3\,{\left (c+d\,x\right )}^2}{8\,{\left (a\,d-b\,c\right )}^3}-\frac {2\,d^3}{3\,\left (a\,d-b\,c\right )}+\frac {35\,b^3\,d^3\,{\left (c+d\,x\right )}^3}{{\left (a\,d-b\,c\right )}^4}+\frac {105\,b^4\,d^3\,{\left (c+d\,x\right )}^4}{8\,{\left (a\,d-b\,c\right )}^5}+\frac {6\,b\,d^3\,\left (c+d\,x\right )}{{\left (a\,d-b\,c\right )}^2}}{{\left (c+d\,x\right )}^{3/2}\,\left (a^3\,d^3-3\,a^2\,b\,c\,d^2+3\,a\,b^2\,c^2\,d-b^3\,c^3\right )+b^3\,{\left (c+d\,x\right )}^{9/2}-\left (3\,b^3\,c-3\,a\,b^2\,d\right )\,{\left (c+d\,x\right )}^{7/2}+{\left (c+d\,x\right )}^{5/2}\,\left (3\,a^2\,b\,d^2-6\,a\,b^2\,c\,d+3\,b^3\,c^2\right )}+\frac {105\,b^{3/2}\,d^3\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {c+d\,x}\,\left (a^5\,d^5-5\,a^4\,b\,c\,d^4+10\,a^3\,b^2\,c^2\,d^3-10\,a^2\,b^3\,c^3\,d^2+5\,a\,b^4\,c^4\,d-b^5\,c^5\right )}{{\left (a\,d-b\,c\right )}^{11/2}}\right )}{8\,{\left (a\,d-b\,c\right )}^{11/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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